What is the molality when 0.75 mol is dissolved in 2.50 L of solvent?

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What is the molality when 0.75 mol is dissolved in 2.50 L of solvent?

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Answer 1 · 2014-06-10T11:39:16

To answer this question we will assume that the solvent is water. The mass of the solvent will be 2.50kg.

NOTE: The density of water is 1g = 1mL

$\frac{2.50 L}{1}$ $(2.50 L)/(1)$ x $\frac{1000 m L}{1 L}$ $(1000 mL)/(1 L)$ x $\frac{1 g}{1 m L}$ $(1 g)/(1 mL)$ x $\frac{1 k g}{1000 g}$ $(1 kg)/(1000g)$ = 2.50 kg

To calculate the molality we use the relationship-

$\frac{m o l s o l u t e}{k g s o l v e n t}$ $(mol solute)/(kg solvent)$ = molality

$\frac{0.75 m o l s o l u t e}{2.50 k g s o l v e n t}$ $(0.75 mol solute)/(2.50 kg solvent)$ = 0.30 $m$ $m$

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What is the molality when 0.75 mol is dissolved in 2.50 L of solvent?

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