How many moles are present in 1.21 X 10^24 molecules of HBr?

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Answer 1 · 2014-07-28T02:53:25

One mole of HBr has 6.02 x 1 $0^23$ molecules of HBr.

1 mole of HBr = 6.02 x 1 $0^23$ molecules of HBr.-----(a)

X mole of HBr has 1.21 x $10^24$ molecules of HBr.

X mole of HBr = 1.21 x $10^24$ molecules of HBr------(b)

Taking ratio of (a) and (b)

X / 1 = 1.21 x $10^24$ / 6.02 x 1 $0^23$

X= 2.009 moles.