Question #e47c7

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Question #e47c7

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Answer 1 · 2014-03-08T17:09:47

40 km/L

Explanation:

6.0 L/101 km = 40 mpg

Convert kilometres to miles :

We could use the conversion factor 1 mi = 1.609 km. Let’s work instead from numbers we know.

$101 k m \times \frac{1000 m}{1 k m} \times \frac{100 c m}{1 m} \times \frac{1 \in}{2.54 c m} \times \frac{1 f t}{12 \in} \times \frac{1 m i}{5280 f t}$ $101 km × (1000 m)/(1 km) × (100 cm)/(1 m) × (1 \in)/(2.54 cm) × (1 ft)/(12 \in) × (1 mi)/(5280 ft)$ = 62.8 mi

(Sorry. This editor converts "in" for "inch" to $\in$ $in$ , the set theory symbol for "in".)

Convert litres to gallons:

1 gal = 3.785 L

$6.0 L \times \frac{1 g a l}{3.785 L}$ $6.0 L × (1 gal)/(3.785 L)$ = 1.6 gal

Calculate fuel consumption:

∴ $\frac{101 k m}{6.0 L} = \frac{62.8 m i}{1.6 g a l}$ $(101 km)/(6.0 L) = (62.8 mi)/(1.6 gal)$ = 40 km/L

Note: I have calculated the answer to only two significant figures, because that is all you gave me for the volume of gasoline. If you need more precision, you will have to recalculate.

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Question #e47c7

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