Question #258e5

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Question #258e5

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Answer 1 · 2014-04-10T17:37:40

8.25 grams of $O_{2}$ $O_2$ has 0.258 moles of Oxygen.

Here's how you figure that out:

Oxygen is one of the 7 diatomic elements, so it is normally $O_{2}$ $O_2$

You find it's molar mass (or mass for one mole of it) by adding up two of the masses from the Periodic Table.

16.00 x 2 = $\frac{32.00 g}{1 m o l O_{2}}$ $(32.00g)/(1molO_2)$

Now, start with the given (8.25 g of $O_{2}$ $O_2$ )

$\frac{8.25 g O_{2}}{1} \cdot \frac{1 m o l O_{2}}{32.00 g} = 0.2578$ $(8.25g O_2)/1*(1molO_2)/(32.00g) = 0.2578$ g, round $\to 3$ $to 3$ sig figs
$= 0.258 g$ $=0.258g$ $O_{2}$ $O_2$

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Question #258e5

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