How can I write the formula for calcium nitride?

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How can I write the formula for calcium nitride?

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Answer 1 · 2014-07-03T06:04:05

$Ca_{3} N_{2}$ $"Ca"""_3"N"_2$

Explanation:

The correct answer is $C a_{3} N_{2}$ $Ca_3N_2$ .

Let us see how we got the answer; Look at the electronic arrangement of Ca and N atom.

Ca ( Z= 20) has 20 electrons with following electronic configuration. 1 $s^{2}$ $s^2$ 2 $s^{2}$ $s^2$ 2 $p^{6}$ $p^6$ 3 $s^{2}$ $s^2$ 3 $p^{6}$ $p^6$ 4 $s^{2}$ $s^2$ .

It loses two electron in its 4s subshell to achieve stability and forms ion $C a^{2 +}$ $Ca^(2+)$ .

$C a^{2 +}$ $Ca^(2+)$ = 1 $s^{2}$ $s^2$ 2 $s^{2}$ $s^2$ 2 $p^{6}$ $p^6$ 3 $s^{2}$ $s^2$ 3 $p^{6}$ $p^6$

N ( Z=7) on the other hand has seven electrons and wants to gain three electrons to achieve stable noble gas configuration.Nitrogen atom on gaining three electrons forms negative nitride ion, $N^{3 -}$ $N^(3-)$ ion.

N ( Z=7) = 1 $s^{2}$ $s^2$ 2 $s^{2}$ $s^2$ 2 $p^{3}$ $p^3$

$N^{- 3}$ $N^-3$ = 1 $s^{2}$ $s^2$ 2 $s^{2}$ $s^2$ 2 $p^{6}$ $p^6$

Two Nitrogen atoms gains three electrons each ( total of six) from three Ca atoms, each Ca atom loses two electrons (total of six) to two Nitrogen atom , in this process each Ca atom becomes $C a^{2 +}$ $Ca^(2+)$ ion and nitrogen atom after gaining three electrons becomes $N^{3 -}$ $N^(3-)$ ion.

![https://www.youtube.com/watch?v=iEFg9uD8eTA]( useruploads.socratic.org )

so in all we have three $C a^{2 +}$ $Ca^(2+)$ ions and two nitride $N^{3 -}$ $N^(3-)$ ions.
so the formula becomes $C a_{3} N_{2}$ $Ca_3N_2$ .

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How can I write the formula for calcium nitride?

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