How do you find the derivative of #y=ln(2x)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Calculus V. Jul 24, 2014 This is the composite of #ln x# and #2x#, so we use the Chain Rule together with the facts that #(2x)'=2# and that #(ln x)'=1/x#: #(ln(2x))'=1/(2x) \times (2x)'=2/(2x)=1/x#. Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 30399 views around the world You can reuse this answer Creative Commons License