What is the midpoint between $A (1, 1, 1)$ $A(1,1,1)$ and $B (4, 1, - 3)$ $B(4,1,-3)$ ?

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What is the midpoint between $A (1, 1, 1)$ $A(1,1,1)$ and $B (4, 1, - 3)$ $B(4,1,-3)$ ?

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Answer 1 · 2014-08-22T02:38:31

The answer is $M (\frac{5}{2}, 1, - 1)$ $M(5/2,1,-1)$ .

The midpoint is one of the easier things to calculate. Remember that mid is a synonym for average. To find the midpoint, we just average the components:

$M = (\frac{P_{1_{x}} + P_{2_{x}}}{2}, \frac{P_{1_{y}} + P_{2_{y}}}{2}, \frac{P_{1_{z}} + P_{2_{z}}}{2})$ $M=((P_(1_x)+P_(2_x))/2, (P_(1_y)+P_(2_y))/2, (P_(1_z)+P_(2_z))/2)$

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What is the midpoint between $A (1, 1, 1)$ $A(1,1,1)$ and $B (4, 1, - 3)$ $B(4,1,-3)$ ?

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