Question

What is the series equivalent of two 1000 W resistors in series?

Answer 1

I think you mean `Omega` and not `W`. The answer is `2000Omega`.

Resistors in series are simply summed (added) up.

If you actually mean `W`, then we need a different calculation:

`P=VI=VV/R=(V^2)/R`
`1000=(V^2)/R`
This is for 1 resistor.

Recall that the voltage is split between the resistors, so total voltage is double, `V_T=2V`. So, summing up the wattage, we get:
`2000=((V_T)^2)/(R_T)=((2V)^2)/(R_T)`
`2(V^2)/R=(4V^2)/(R_T)`
`R_T=2R`

Since we are not provided with any voltage or resistance, we simply have to leave the answer as `R_T=2R`, where `R` is the resistance of 1 resistor.