How do you find the limit #lim_(x->4)(x^3-64)/(x^2-8x+16)# ?
1 Answer
Sep 17, 2014
First factor the denominator...
Now factor the numerator...
Divide numerator and denominator by x-4...
Replace all x's with the limit being approached (4)...
Combine terms...
The limit approaches infinity since division by 0 is undefined, but division by 0 also approaches infinity.