How do you find the area under the graph of f(x)=sin(x) on the interval [π,π] ?

1 Answer
Sep 17, 2014

For this question to have to set up a definite integral.

We see that this integral is bounded from π to π inclusive.

Also remember that after we integrate we have to subtract the result of the lower bound, π from that of the higher bound, π.

Be careful with all of those double negatives which resolve to positives.

Lastly, remember from the unit circle that both cos(π) and cos(π) resolve to -1.

ππsin(x)dx

=[cos(x)]ππ=cos(π)(cos(π))

=(1)((1))=11=0

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