How do you solve for x in $x - \frac{5}{6} = \frac{3}{8}$ $x - \frac{5}{6} = \frac{3}{8}$ ?

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Answer 1 · 2014-09-28T14:05:51

$x - \frac{5}{6} = \frac{3}{8}$ $x - 5/6 = 3/8$

adding $\frac{5}{6}$ $5/6$ to both sides of equation ;

$x - \frac{5}{6} + \frac{5}{6} = \frac{3}{8} + \frac{5}{6}$ $x -5/6 + 5/6 = 3/8 + 5/6$

$x = \frac{3}{8} + \frac{5}{6}$ $x = 3/8 + 5/6$

LCM of $6$ $6$ and $8$ $8$ is $48$ $48$

$x = \frac{18 + 40}{48}$ $x = (18 + 40 ) / 48$

$x = \frac{58}{48}$ $x = 58 /48$

How do you solve for x in x−56=38 x - \frac{5}{6} = \frac{3}{8}?