How do you solve for y in $\frac{3}{4} = - \frac{1}{2} \cdot y$ $\frac{3}{4} = - \frac{1}{2} \cdot y$ ?

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Answer 1 · 2014-09-28T14:08:22

$\frac{3}{4} = - \frac{1}{2} (y)$ $3/4 = -1/2 (y)$

cross multiplying we get;

$3 \cdot 2 = - y \cdot 4$ $3 * 2 = -y * 4$

$6 = - 4 y$ $6 = -4y$

dividing both sides by $- 4$ $-4$

$\frac{6}{- 4} = \frac{- 4 y}{- 4}$ $6 /-4 = (-4y) /-4$

$y = - \frac{3}{2}$ $y = -3/2$

How do you solve for y in 34=−12⋅y\frac{3}{4} = - \frac{1}{2} \cdot y?