How do you solve for x in $3 (x - 1) = 2 (x + 3)$ $3(x-1) = 2 (x+3)$ ?

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Answer 1 · 2014-09-28T17:53:35

3 (x-1) = 2 (x + 3)

3.x + 3 (-1) = 2.x + 2.3

$3 x + (- 3) = 2 x + 6$ $3x + (-3) = 2x +6$

$3 x - 3 = 2 x + 6$ $3x -3 = 2x +6$

for combining like terms either you can subtract $2 x$ $2x$ from the Left Hand Side ( LHS) or subtract $3 x$ $3x$ from the Right Hand Side ( RHS).

$3 x - 3 - 3 x = 2 x + 6 - 3 x$ $3x -3 -3x = 2x + 6 -3x$

$- 3 = - x + 6$ $-3 = -x + 6$

subtracting $6$ $6$ from both sides;

$- 3 - 6 = - x + 6 - 6$ $-3 -6 = -x +6 -6$

$- 9 = - x$ $-9 = -x$

$x = 9$ $x = 9$

How do you solve for x in 3(x−1)=2(x+3)3(x-1) = 2 (x+3)?