What is the graph of $y=sin (x/3)$ ?

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Answer 1 · 2014-10-06T04:45:44

First, calculate the period.

$omega=(2pi)/B=(2pi)/(1/3)=((2pi)/1)*(3/1)=6pi$

Break up $6pi$ into fourth by dividing by $4$ .

$(6pi)/(4)=(3pi)/(2)$

$0,(3pi)/(2),3pi,(9pi)/2,6pi ->x$ -values

These $x$ values correspond to ...

$sin(0)=0$

$sin((pi)/(2))=1$

$sin(pi)=0$

$sin((3pi)/2)=-1$

$sin(2pi)=0$

Enter the function using the Y= button

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Press the WINDOW button.
Enter the Xmin of $0$ and Xmax of $6pi$ .
The calculator converts $6pi$ to its decimal equivalent.

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Press the GRAPH button.

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What is the graph of y=sin (x/3)y=sin (x/3)?