Question #f4231

1 Answer

"AgNO"_text(3(aq]) + "HCl"_text((aq]) -> "AgCl"_text((s]) + "HNO"_text(3(aq])AgNO3(aq]+HCl(aq]AgCl(s]+HNO3(aq]

Explanation:

To write the complete ionic equation:

  • Start with a balanced molecular equation.
  • Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions
  • indicate the correct formula and charge of each ion
    indicate the correct number of each ion
    write (aq) after each ion
  • Bring down all compounds with (s), (l), or (g) unchanged.

The molecular equation is

"AgNO"_text(3(aq]) + "HCl"_text((aq]) -> "AgCl"_text((s]) + "HNO"_text(3(aq])AgNO3(aq]+HCl(aq]AgCl(s]+HNO3(aq]

How did I get this equation? Consider each reactant or product separately:

"1 mole"1 mole of "AgNO"_3AgNO3 contains "1 mole"1 mole of "Ag"^+Ag+ and "1 mole"1 mole of "NO"_3^-NO3 ions.

"Ag"_text((aq])^(+) + "NO"_text(3(aq])^(-) + "H"_text((aq])^(+) + "Cl"_text((aq])^(-) -> "AgCl"_text((s]) darr + "H"_text((aq])^(+) + "NO"_text(3(aq])^(-)Ag+(aq]+NO3(aq]+H+(aq]+Cl(aq]AgCl(s]+H+(aq]+NO3(aq]

The net ionic equation is

"Ag"_text((aq])^(+) + "Cl"_text((aq])^(-) -> "AgCl"_text((s]) darrAg+(aq]+Cl(aq]AgCl(s]