How do you simplify $7 (x + 2)$ $7(x+2)$ ?

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Answer 1 · 2014-09-28T18:05:33

$7 (x + 2)$ $7 (x+2)$

$7 \cdot x + 7 \cdot 2$ $7*x + 7*2$

$7 x + 14$ $7x + 14$

in order to solve for x assume, the equation to be equal to zero;

$7 x + 14 = 0$ $7x + 14 = 0$

subtract $14$ $14$ from both sides

$7 x + 14 - 14 = 0 - 14$ $7x +14 -14 = 0-14$

$7 x = - 14$ $7x = -14$

dividing both the sides by $7$ $7$ gives;

$\frac{7 x}{7} = - \frac{14}{7}$ $(7x) /7 = -14 /7$

$x = - 2$ $x = -2$

How do you simplify 7(x+2)7(x+2)?