What is the graph of 4x − 2y + z = −14x2y+z=1?

1 Answer
Oct 18, 2014

By rewriting a bit,

4(x-0)-2(y-0)+1(z+1)=04(x0)2(y0)+1(z+1)=0,

which is a plane passing through the point (0,0,-1)(0,0,1) with the normal vector vec{n}=(4,-2,1)n=(4,2,1).


I hope that this was helpful.

This is a visual representation of the plane in a Cartesian system of coordinates

Image generated by Geogebra