What is the graph of $4 x - 2 y + z = - 1$ $4x − 2y + z = −1$ ?

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Answer 1 · 2014-10-18T23:17:31

By rewriting a bit,

$4 (x - 0) - 2 (y - 0) + 1 (z + 1) = 0$ $4(x-0)-2(y-0)+1(z+1)=0$ ,

which is a plane passing through the point $(0, 0, - 1)$ $(0,0,-1)$ with the normal vector $\to n = (4, - 2, 1)$ $vec{n}=(4,-2,1)$ .

I hope that this was helpful.

This is a visual representation of the plane in a Cartesian system of coordinates

Image generated by Geogebra

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