Question

Question #753ae

Answer 1

`F(θ)=(sec(theta)tan(theta))/(1+sec(θ))^2`

Explanation :

`F(θ)=sec(θ)/(1+sec(θ))`

let's `y=f(x)/g(x)`

Using Quotient Rule,

`y'=(f'(x)g(x)-f(x)g'(x))/(g(x))^2`

Similarly following for the given problem and differentiating with respect `theta`,

`F(θ)=sec(θ)/(1+sec(θ))`

`F(θ)=((1+sec(θ))(sec(theta)tan(theta))-sec(theta)(sec(theta)tan(theta)))/(1+sec(θ))^2`

`F(θ)=(sec(theta)tan(theta))/(1+sec(θ))^2`