Question #bf67e

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Answer 1 · 2014-11-17T20:39:54

Wow! Mad props to the snorkeler who can dive to a depth of 42m! Very impressive!

To solve:
$P_{1}$ $P_1$ = 1.0atm
$P_{2}$ $P_2$ = 5.2atm
$V_{1}$ $V_1$ = 5.0L
$V_{2}$ $V_2$ = ?

$P_{1} V_{1}$ $P_1V_1$ = $P_{2} V_{2}$ $P_2V_2$ solve for $V_{2}$ $V_2$

$V_{2}$ $V_2$ = ( $P_{1} V_{1}$ $P_1V_1$ )/ $P_{2}$ $P_2$

$V_{2}$ $V_2$ = (1atm*5.0L)/ $5.2 a t m$ $5.2atm$

$V_{2}$ $V_2$ = 0.96L

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Hope this helps!
Noel P.