Question

Question #3177e

Answer 1

The line perpendicular to `3x+9y=0` has the equation `y=3x`

`3x+9y=0`

Putting this into the form `y=mx+c` we get:

`y=(-x)/(3)`

So `m=-(1)/(3)`

If two lines A and B are perpendicular then gradient of

B = -1/gradient of A

So gradient of B `(-1)/(-(1)/(3)) =3`

So the perpendicular line has the equation `y=3x`

Should really be under Algebra but there you go.