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Answer 1 · 2014-11-26T15:30:29

The reaction of barium and nitrogen will result in the formation of barium nitride.

Here is the reaction...

$3 B a (s) + N_{2} (g) \to B a_{3} N_{2} (s)$ $3Ba(s) + N_2(g) -> Ba_3N_2(s)$

The barium atoms will lose 2 electrons and form ions with a +2 charge. The nitrogen atoms gain three electrons forming ions with a -3 charge.

The compound must form with a 3:2 ratio to produce a compound which is electrically neutral (no overall charge).

$B a^{2 +} B a^{2 +} B a^{2 +} N^{3 -} N^{3 -}$ $Ba^(2+)Ba^(2+)Ba^(2+)N^(3-)N^(3-)$

This video illustrates the transfer of electrons that takes place in reactions that form ionic compounds.

Hope this helps!