Question

Question #32ae2

Answer 1

You need to use the combined gas law

`((p_1)(v_1))/T_1 = ((p_2)(v_2))/T_2`

The temperatures must be absolute....in the given problem...they are already in absolute temp

Substitute the values,

`(1.34 atm )(215 mL)/(297 K)` = `(1.52 atm)(V2)/(339 K)`

then solve for V2,

`V2= (1.34 atm)(215 mL)(339 K)/(297 K * 1.52 atm)`

K cancels, atm cancels,,, this will leave you a unit of volume

therefore, V2 = 216.34 mL