How can I calculate pH of $N a O H$ $NaOH$ ?

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How can I calculate pH of $N a O H$ $NaOH$ ?

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Answer 1 · 2014-12-05T23:50:38

Assuming that you either start with, or can determine a molar concentration for $N a O H$ $NaOH$ , the easiest way to get to $p H$ $pH$ is by calculating $p O H$ $pOH$ .

$N a O H$ $NaOH$ is a strong base, which means it dissociates completely

$N a O H (a q) + H_{2} O (a q) \Leftrightarrow N a^{+} (a q) + O H^{-} (a q)$ $NaOH(aq) + H_2O(aq) <=> Na^+ (aq) + OH^(-) (aq)$

The concentrations of $N a^{+}$ $Na^+$ and $O H^{-}$ $OH^-$ are equal to the intial concentration of $N a O H$ $NaOH$ , let's say $X$ $X$ . You can now determine $p O H$ $pOH$ by using

$p O H = - log (X)$ $pOH = -log(X)$ , which then gets you to

$p H = 14 - p O H$ $pH = 14 - pOH$

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How can I calculate pH of $N a O H$ $NaOH$ ?

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