Question

Question #95964

Answer 1

You need to start by using the definition of molarity to determine how many moles of `HCl` can be found in `75mL` of solution.

`n_(HCl) = C * V_(solution) = 1.50 (mol es)/L * 75 * 10^(-3) L = 011 mol es`

Now, knowing that `HCl`'s molar mass is `36.5 g/(mol e)`, we can determine the mass of `HCl` dissolved in `75mL` by

`m_(HCl) = n_(HCl) * 36.5 g/(mol e) = 0.11 mol es * 36.5 g/(mol e) = 4.0 g`