Question #c8320

1 Answer

#log(0.01^2/x^3) = -10.64#
I assume that #log# means the logarithm with base #10#.

By the property #log(a/b)=log(a)-log(b)# we get:
#log(0.01^2) - log(x^3) = -10.64#
#log((10^{-2})^2) +10.64=log(x^3)#
#log(10^{-4}) +10.64=log(x^3)#
By the property #log(a^b) =b log(a)#
#-4 log(10) +10.64=3 log(x)#
#-4 +10.64=3 log(x)#
#6.64=3 log(x)#
#6.64/3=log(x)#
By definition of logarithm with base #10#
#x=10^{6.64/3} approx 163,43#