How do you work out the percentage of each element in sodium hydrogen sulfate ?

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Answer 1 · 2015-02-16T19:49:43

Work out the $M_{r}$ $M_r$ by adding up the $A_{r}$ $A_r$ values as they occur in the formula, then work out the % contribution each element makes.

Work out the $M_{r}$ $M_r$ by adding up the $A_{r}$ $A_r$ values as they occur in the formula.

I'll use approximate values:

$A_{r} N a = 23$ $A_rNa=23$

$A_{r} H = 1$ $A_rH=1$

$A_{r} S = 32$ $A_rS=32$

$A_{r} O = 16$ $A_rO=16$

$M_{r}$ $M_r$ of $N a H S O_{4}$ $NaHSO_4$ :

$= 23 + 1 + 32 + (4 \times 16) = 120$ $=23+1+32+(4xx16)=120$

Then work out the % contribution each element makes:

% $N a = \frac{23}{120} \times 100 = 19.16$ $Na=(23)/(120)xx100=19.16$

% $H = \frac{1}{120} \times 100 = 0.833$ $H=(1)/(120)xx100=0.833$

% $S = \frac{32}{120} \times 100 = 26.66$ $S=(32)/(120)xx100=26.66$

% $O = \frac{64}{120} \times 100 = 53.33$ $O=(64)/(120)xx100=53.33$

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