How do you sketch the graph of #x^2+y^2+8x-6y+16=0#?
1 Answer
Feb 18, 2015
Hello,
Use canonical form :
Indeed, you have
Same thing with
So, your equation has a good looking form :
or better :
You recognize the circle of center
graph{(x+4)^2+(y-3)^2=9 [-13.87, 6.13, -2.22, 7.78]}