Question #9cf7b

Question

2129 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-02-23T20:17:05

Hello,

Answer.

or

Explanation

You have to solve $2x+2=x^2-2$ , so $x^2-2x-4=0$ .

Remark that $(x-2)^2=x^2-2x+4$ , therefore :
$x^2-2x-4 = (x-2)^2-8$ .

So, you have to solve $(x-2)^2=8$ .
Solutions are $x-2 = \pm sqrt(8) = pm 2sqrt(2)$ , it means
$x = 2 - 2 sqrt(2)$ or $x=2+2 sqrt(2)$ .

Finally, calculate corresponding $y$ for each value of $x$ : because $y = 2x+2$ , it's easy !.