Question

Question #4f42d

Answer 1

The condition for your line to be perpendicular to the given one is that:
`m_1*m_2=-1`
where `m` is the gradient (or slope) of the line.
Your line CA has slope = `m_1=(Deltay)/(Deltax)=(2-(-3))/(-8-7)=-1/3`
So your perpendicular line will have slope `m_2=3`.

Now, given the coordinates of a point such as (`x_3,y_3`), you can determine the equation of a specific line perpendicular to CA as:
`y-y_3=m_2(x-x_3)`

hope it helps