Question

Question #09cb4

Answer 1

You do this by ratios.

Calcium oxide `CaO` has a molecular mass of:
`40(Ca)+16(O)=56` of which `40` is `Ca`

So the `14 g` of calcium oxide contains:

`14.0/56=(m_(Ca))/40->m_(Ca)=(40*14)/56=10g` of calcium.

On a total of `50.0g` of bone

This is `10/50xx100%=20%`