What is the linear equation 10y=-6x-910y=−6x−9 in standard form?

1 Answer
Alexander Garcia · Meave60
Mar 12, 2015

The equation for a line in standard form, or slope-intercept form, is y = mx + by=mx+b, where mm is the slope, and bb is the y-intercept.

To convert the equation 10y = -6x - 910y=−6x−9 to standard form, do the following:

  1. Divide both sides of the equation by 10:

    (10y)/10=-(6x)/10 - 9/1010y10=−6x10−910
    y=-(6x)/10 - 9/10y=−6x10−910

  2. Reduce -(6x)/(10)−6x10 to -(3x)/(5)−3x5, and you will get the equation in standard form:

    y = -3/5x - 9/10y=−35x−910.

The slope (mm) is -3/5−35, and the y-intercept (bb) is -9/10−910.

Graphically, this is what the function looks like:

enter image source here

Usually, if the question asks where does a line intersect the y-axis or the y-intercept, it is usually written in terms of a point on a graph where x = 0.
In this equation, the point is (0,-9/10)(0,−910).

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