Question

Question #1068b

Answer 1

You have to distinguish between heat capacity C and specific heat c, which is heat capacity per gram, so `C=c*m`

We now set up an equation, because heat gained by the water equals heat lost by the pellet. From both we know start and end temperature, and thus the change `DeltaT`
The specific heat of water `c_w` can be found to be `4.18J//g*^oC`

So here goes (water left, pellet right):

`c_w*m*DeltaT_w=C_p*DeltaT_p`

Fill in what we know:

`4.18*m*(54.8-22.7)=52*(121-54.8)->`

`124.2*m=3442.4->m=27.7g`