How do you write the slope intercept form of the equation of the line through the given point (-1,-1) with the given slope 4?

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Answer 1 · 2015-03-30T11:50:15

#y= 4x+3#

The standard slope intercept form of any line is

#y=mx +b#

In this case #m=4#,

hence equation would be

#y =4x+b#.

Since this line passes through #(-1,-1)#,
Plug in #x= -1# and #y= -1#
This would give

#-1= -4+b.#

Add #4# on both sides and get

#b= 3#

The required equation would be

#y= 4x+3#.