How do you solve the system of equations #2x+3y=6# and #3x+3y=14#?

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Answer 1 · 2015-04-01T17:16:04

#x = 8, y = -10/3#

Our aim is finding a similarity in the two equations. In this problem, we already have it: #3y#

So, lets rewrite the second equation:

#2)# #3x + 3y = 14#
#3y = 14 - 3x#

Now, we can replace #3y# with #14-3x# in the first equation.

#2x + (14-3x)=6#
#2x+14-3x=6#
#-x=-8#
#x = 8#

Now, we know the value of #x#. By using either first or second equation we can calculate the value of #y#. Lets use the second "#2)#" equation.

#2)# #3x + 3y = 14#
#3*8 + 3y = 14#
#24+3y=14#
#3y = -10#
#y=-10/3#