How do you write an equation of a line that passes through (4,2) and is parallel to the line whose equation is #y=2x-4#?

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Answer 1 · 2015-04-02T13:27:52

The answer is #d = 2x-6#

I use #y = mx+n# line equation form to solve these problems. (#m# is the slope)

Parallel lines have the same slope. So our unkown line has a slope of #2#.

(lets call our unknown line as #d#)

#d = 2x + n#

Now plug the given point to find #n#

#2 = 2*4+n#
#n=-6#

So here is the equation:

#d=2x-6#