How do you write the equation of the line that passes through the points P(8, -1), Q(0, -7)?

1 Answer
Apr 3, 2015

The answer is: #y = 6/8x-7#

First, we need to find the slope of the line. Slope can be found as:

#m = (y_1 - y_2)/(x_1-x_2)#

#m = (-1-(-7))/(8-0) = 6/8#

So our incomplete line equation is:

#y = 6/8x+n#

Lets plug one the points to the equation to find the value of #n#

I will plug #P#

#-1 = 6/8*8 + n#

#-1 = 6+n#

#n=-7#

So the line equation is:

#y = 6/8x-7#