How do you solve x+y=3x+y=3; x+2y=5x+2y=5?

1 Answer
Apr 7, 2015
  • We can solve for the values of x and y using the 'Elimination by Substitution' method.

  • Let's number the equations first:
    x+y=3x+y=3 ------(1)
    x+2y=5x+2y=5------(2)

In (1), by transposing yy to the other side, we get
x= 3 - yx=3y
Substituting this value of xx in (2), we get
(3-y)+2y = 5(3y)+2y=5
3+y=53+y=5
y=5-3y=53
y=2y=2
Here, we eliminated xx by substituting its value in (2)

  • We Substitute this value of yy in (1) to get
    x+2=3x+2=3
    x=3-2x=32
    x=1x=1

  • The Solution for the equations (1) and (2) is:
    x=1 , y=2x=1,y=2

  • Once we arrive at a solution, it is a good idea to VERIFY our answer

Substituting x=1 , y=2x=1,y=2 in (1) we get
Left Hand Side: x+y = 1+2 = 3x+y=1+2=3(Right Hand Side)

Substituting x=1 , y=2x=1,y=2 in (2) we get
Left Hand Side: x+y = 1+(2*2) = 5x+y=1+(22)=5(Right Hand Side)

We have verified our answer, and we can be sure that it's correct.