Question

A cyclist increases his kinetic energy from 11 00 J to 5 200 J in 12 s. How can I calculate his power output during this time?

Answer 1

Power is the rate of change of output energy.

`P=dE/dt` or `P=(DeltaE)/(Deltat)`

Having said that, the change in energy

`DeltaE= E_f - E_i=5200J-1100J`

and your time interval `Deltat=12s`.

Voila!