How do you solve #x-15=28#? Algebra Linear Equations One-Step Equations and Inverse Operations 1 Answer Pris Apr 10, 2015 Firstly, you have to isolate #x# away from other values. You can do that by adding #15# to the left hand side and the right hand side of the equation. #x-15+15=28+15# #x=43# Answer link Related questions What are One-Step Equations? How do you check solutions when solving one step equations? How do you solve one step equations involving addition and subtraction? How do inverse operations help solve equations? What are some examples of inverse operations? How do you solve for x in #x + 11 = 7#? How do you solve for x in #7x = 21#? How do you solve for x in # x - \frac{5}{6} = \frac{3}{8}#? How do you solve for f in #\frac{7f}{11} = \frac{7}{11}#? How do you solve for y in #\frac{3}{4} = - \frac{1}{2} \cdot y#? See all questions in One-Step Equations and Inverse Operations Impact of this question 4486 views around the world You can reuse this answer Creative Commons License