How do to you factor 8x^3 + 125y^68x3+125y6?

1 Answer
Apr 14, 2015

We can modify the expression to use the Sum of Cubes formula to factorise it.

8x^3 + 125y^6 = (2x)^3 + (5y^2)^38x3+125y6=(2x)3+(5y2)3

The formula says :color(blue)(a^3 + b^3 = (a + b)(a^2-ab+b^2)a3+b3=(a+b)(a2ab+b2)

Here, aa is 2x2x and bb is 5y^25y2

(2x)^3 + (5y^2)^3 = (2x + 5y^2){(2x)^2 - (2x)(5y^2) + (5y^2)^2}(2x)3+(5y2)3=(2x+5y2){(2x)2(2x)(5y2)+(5y2)2}

color(green)(= (2x + 5y^2){4x^2 - 10xy^2 + 25y^4}=(2x+5y2){4x210xy2+25y4}

As none of the factors can be factorised further, this becomes the Factorised form of 8x^3 + 125y^68x3+125y6