Mark’s scores on his first nine assignments are: 10,10,9,9,10,8,9,10,and 8. What are the mean, median, mode, and range of his scores?

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Answer 1 · 2015-04-20T15:57:12

Mean $= 9.22$ $=9.22$
Median $= 9$ $=9$
Mode $= 10$ $=10$
Range $= 2$ $=2$

mean (average)
x tally mark frequency
10 |||| 4
9 ||| 3
8 || 2

Total f x $= (10 \times 4) + (9 \times 3) + (8 \times 2)$ $= (10 xx 4)+(9 xx 3)+(8 xx 2)$

$= 40 + 27 + 16 = 83$ $= 40+27+16 = 83$

Total frequency $= 4 + 3 + 2$ $= 4+3+2$

$= 9$ $= 9$

$¯ x = \frac{83}{9}$ $bar x= (83)/ 9$

$= 9.22$ $= 9.22$
Given -
$10, 10, 9, 9, 10, 8, 9, 10, and 8$ $10,10,9,9,10,8,9,10,and 8$

Arrange them in the ascending order
$8, 8, 9, 9, 9, 10, 10, 10, 10$ $8, 8, 9, 9, 9, 10, 10, 10, 10$

median $= (\frac{n + 1}{2})$ $= ((n+1)/ 2)$ th item

$= \frac{9 + 1}{2} = 5$ $= (9+1)/2=5$ th item

$= 9$ $=9$

Mode = that item which occurs more umber of times

mode $= 10$ $= 10$

Range = Largest Value - Smallest Value
range $= (10 - 8)$ $= (10-8)$

Range = 2