How do you find the limit of #( ln(4x) - ln(x) ) / ( ln(x) )# as x approaches 1?

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Answer 1 · 2015-04-20T13:25:39

Using the property of logarithm:

#log(ab)=loga+logb# (with #a,b>0#)

#lim_(xrarr1)(ln(4x)-ln(x))/(ln(x))=lim_(xrarr1)(log4+logx-logx)/logx=#

#=lim_(xrarr1)log4/logx=oo#.

Answer 2 · 2015-04-21T00:31:03

Apr 21, 2015

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