Question #90a50

1 Answer
Alexander L.
Apr 22, 2015

The graph in essence is not a linear graph.

Hence, we would want to transform the graph with a sort of operator.

#T=AL^c#
#LogT=Log(AL^c)#
#LogT=LogA+LogL^c#
#LogT=LogA+cLogL#

You can now recognize this as #Y=C+MX#

#Y=LogT#
#C=LogA#
#M=c#
#X=LogL#

Related questions
Impact of this question
799 views around the world
You can reuse this answer
Creative Commons License