How do you find the derivative of #y=ln(1+e^x/1-e^x)#?
2 Answers
I think that this was not the function that you intended to write (probably you omitted parentheses, which are essential when one writes in-line fractions). In fact, you can rewrite that function as follows:
The derivative of a constant function is
I'll try to infer the function that you wanted to write:
The code to render this properly is f(x)=ln((1+e^x)/(1-e^x)) (notice the usage of parentheses).
This is a function composition. Given two functions
In this particular case
The derivative of
and the derivative of
So
I assume you want to differentiate:
You could use
Or, simplifying: