How do you find the six trigonometric functions of 420 degrees? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. ยท Nghi N May 3, 2015 sin 420 = sin (60 + 360) = sin 60 = (sqrt3)/2(1) cos 420 = cos (60 + 360) = cos 60 = 1/2 (2) tan 420 = ((1))/((2) )= sqrt3 cot 420 = 1/(sqrt3) = (sqrt3)/3 sec 420 = 1/cos 420 = 2 sin 420 = 1/sin 420 = (2sqrt3)/3 Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for 140^\circ? How do you find the value of cot 300^@? What is the value of sin -45^@? How do you find the trigonometric functions of values that are greater than 360^@? How do you use the reference angles to find sin210cos330-tan 135? How do you know if sin 30 = sin 150? How do you show that (costheta)(sectheta) = 1 if theta=pi/4? See all questions in Trigonometric Functions of Any Angle Impact of this question 25628 views around the world You can reuse this answer Creative Commons License
