How do you find the solution of the system of equations $x+3y=12$ and $x-3y= -6$ ?

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Answer 1 · 2015-05-04T07:45:04

Solving by elimination and substitution:

$x+3y = 12$
$x-3y = -6$

on adding the two equations $3y$ gets cancelled
$x + cancel(3y) = 12$
$x - cancel(3y) = -6$

$2x = 6$
$x = 6/2 = 3$

substituting this value of $x$ in equation 1:

$x + 3y = 12$
$3+ 3y = 12$
$3y = 12 - 3$
$3y = 9$
$y = 3$

the solution for the system of equations are :
$color(blue)x=3$
$color(blue)y=3$

How do you find the solution of the system of equations x+3y=12 x+3y=12 and x-3y= -6x-3y= -6?