Question #56298

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Question #56298

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Answer 1 · 2015-05-04T23:43:34

$r^{2} + 4 r + 1 = 0$ $r^2+4r+1 = 0$

$r^{2} + 4 r + 2^{2} - 2^{2} + 1 = 0 insert appropriate value to make into a square$ $color(red)(r^2+4r+2^2) -2^2 +1 =0 " insert appropriate value to make into a square"$

${(r + 2)}^{2} - 3 = 0$ $color(red)((r+2)^2) -3 = 0$

${(r + 2)}^{2} = 3$ $(r+2)^2 = 3$

$r + 2 = \pm \sqrt{3}$ $r+2 = +-sqrt(3)$

$r = - 2 \pm \sqrt{3}$ $r = -2 +-sqrt(3)$

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Question #56298

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