How do you use the laws of exponents to simplify the expression ${(y^{- 4})}^{- \frac{3}{4}}$ $(y^-4)^(-3/4)$ ?

Question

1970 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-07T11:44:32

One of the laws of exponents says:
${(b^{m})}^{n} = b^{m \times n}$ $(b^m)^n =b^(mxxn)$

So ${(y^{- 4})}^{- \frac{3}{4}}$ $(y^(-4))^(-3/4)$

$= y^{(- 4) \times (- \frac{3}{4})}$ $= y^((-4)xx(-3/4))$

$= y^{3}$ $=y^3$

How do you use the laws of exponents to simplify the expression (y−4)−34 (y^-4)^(-3/4)?