How do you multiply $((5x)/(3x +1)) - (1/(9x + 3)) = (7/6)$ ?

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Answer 1 · 2015-05-09T11:45:04

$(9x +3)$ can be written as $3(3x +1)$ and 6 can be written as $3 xx 2$

The L.C.M of $(3x +1), 3(3x + 1)$ and $3 xx 2$ $= 6(3x+1)$

$(5x xx 6)/(6xx(3x+1)$ $- (1 xx2)/ (6xx(3x+1)$ $= (7 xx(3x+1))/(6 xx (3x +1))$

$(30x - 2) / (6xx(3x+1)$ $= (21x +7)/ (6xx(3x+1)$

$(30x - 2) / cancel(6xx(3x+1)$ $= (21x +7)/ cancel(6xx(3x+1)$

$9x = 7+2$

$x = 9/9$

$x =1$

How do you multiply ((5x)/(3x +1)) - (1/(9x + 3)) = (7/6)((5x)/(3x +1)) - (1/(9x + 3)) = (7/6)?