How do you factor #3x^2-7x+4#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Nghi N. · Nghi N May 12, 2015 #f(x) = 3x^2 - 7x + 4# Reminder: When (a + b + c) = 0, one factor is (x - 1) and the other is #(x - c/a) = (x - 4/3)# #f(x) = 3(x - 1)(x - 4/3) = (x - 1)(3x - 4)# Check. Develop #f(x) = 3x^2 - 4x - 3x + 4 = 3x^2 - 7x + 4.# Correct Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 5794 views around the world You can reuse this answer Creative Commons License