How do you factor $3x^2-7x+4$ ?

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Answer 1 · 2015-05-12T04:45:33

$f(x) = 3x^2 - 7x + 4$

Reminder: When (a + b + c) = 0, one factor is (x - 1) and the other is
$(x - c/a) = (x - 4/3)$

$f(x) = 3(x - 1)(x - 4/3) = (x - 1)(3x - 4)$

Check. Develop $f(x) = 3x^2 - 4x - 3x + 4 = 3x^2 - 7x + 4.$ Correct

How do you factor 3x^2-7x+43x^2-7x+4?